Array.prototype.findIndex()
The findIndex()
method returns the index of the first element in an array that satisfies the provided testing function.
If no elements satisfy the testing function, -1 is returned.
See also the find()
method, which returns the first element that satisfies the testing function (rather than its index).
Try it
Syntax
js
findIndex(callbackFn)
findIndex(callbackFn, thisArg)
Parameters
callbackFn
-
A function to execute for each element in the array. It should return a truthy value to indicate a matching element has been found, and a falsy value otherwise. The function is called with the following arguments:
element
-
The current element being processed in the array.
index
-
The index of the current element being processed in the array.
array
-
The array
findIndex()
was called upon.
thisArg
Optional-
A value to use as
this
when executingcallbackFn
. See iterative methods.
Return value
The index of the first element in the array that passes the test. Otherwise, -1
.
Description
The findIndex()
is an iterative method. It calls a provided callbackFn
function once for each element in an array in ascending-index order, until callbackFn
returns a truthy value. findIndex()
then returns the index of that element and stops iterating through the array. If callbackFn
never returns a truthy value, findIndex()
returns -1
.
callbackFn
is invoked for every index of the array, not just those with assigned values. Empty slots in sparse arrays behave the same as undefined
.
findIndex()
does not mutate the array on which it is called, but the function provided as callbackFn
can. Note, however, that the length of the array is saved before the first invocation of callbackFn
. Therefore:
callbackFn
will not visit any elements added beyond the array's initial length when the call tofindIndex()
began.- Changes to already-visited indexes do not cause
callbackFn
to be invoked on them again. - If an existing, yet-unvisited element of the array is changed by
callbackFn
, its value passed to thecallbackFn
will be the value at the time that element gets visited. Deleted elements are visited as if they wereundefined
.
Warning: Concurrent modifications of the kind described above frequently lead to hard-to-understand code and are generally to be avoided (except in special cases).
The findIndex()
method is generic. It only expects the this
value to have a length
property and integer-keyed properties.
Examples
Find the index of a prime number in an array
The following example returns the index of the first element in the array that is a prime number, or -1
if there is no prime number.
js
function isPrime(element) {
if (element % 2 === 0 || element < 2) {
return false;
}
for (let factor = 3; factor <= Math.sqrt(element); factor += 2) {
if (element % factor === 0) {
return false;
}
}
return true;
}
console.log([4, 6, 8, 9, 12].findIndex(isPrime)); // -1, not found
console.log([4, 6, 7, 9, 12].findIndex(isPrime)); // 2 (array[2] is 7)
Using findIndex() on sparse arrays
You can search for undefined
in a sparse array and get the index of an empty slot.
js
console.log([1, , 3].findIndex((x) => x === undefined)); // 1
Calling findIndex() on non-array objects
The findIndex()
method reads the length
property of this
and then accesses each property whose key is a nonnegative integer less than length
.
js
const arrayLike = {
length: 3,
"-1": 0.1, // ignored by findIndex() since -1 < 0
0: 2,
1: 7.3,
2: 4,
};
console.log(
Array.prototype.findIndex.call(arrayLike, (x) => !Number.isInteger(x)),
); // 1
Specifications
Specification |
---|
ECMAScript Language Specification # sec-array.prototype.findindex |
Browser compatibility
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